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90=x^2-13x
We move all terms to the left:
90-(x^2-13x)=0
We get rid of parentheses
-x^2+13x+90=0
We add all the numbers together, and all the variables
-1x^2+13x+90=0
a = -1; b = 13; c = +90;
Δ = b2-4ac
Δ = 132-4·(-1)·90
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-23}{2*-1}=\frac{-36}{-2} =+18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+23}{2*-1}=\frac{10}{-2} =-5 $
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